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1、數(shù)據(jù)庫(kù)連接配置頁(yè)面:connectvars.php
復(fù)制代碼 代碼如下:
<?php
//數(shù)據(jù)庫(kù)的位置
define('DB_HOST', 'localhost');
//用戶(hù)名
define('DB_USER', 'root');
//口令
define('DB_PASSWORD', '19900101');
//數(shù)據(jù)庫(kù)名
define('DB_NAME','test') ;
?>
2、登錄頁(yè)面:logIn.php
復(fù)制代碼 代碼如下:
<?php
//插入連接數(shù)據(jù)庫(kù)的相關(guān)信息
require_once 'connectvars.php';
$error_msg = "";
//判斷用戶(hù)是否已經(jīng)設(shè)置cookie,如果未設(shè)置$_COOKIE['user_id']時(shí),執(zhí)行以下代碼
if(!isset($_COOKIE['user_id'])){
if(isset($_POST['submit'])){//判斷用戶(hù)是否提交登錄表單,如果是則執(zhí)行如下代碼
$dbc = mysqli_connect(DB_HOST,DB_USER,DB_PASSWORD,DB_NAME);
$user_username = mysqli_real_escape_string($dbc,trim($_POST['username']));
$user_password = mysqli_real_escape_string($dbc,trim($_POST['password']));
if(!empty($user_username)&&!empty($user_password)){
//MySql中的SHA()函數(shù)用于對(duì)字符串進(jìn)行單向加密
$query = "SELECT user_id, username FROM mismatch_user WHERE username = '$user_username' AND "."password = SHA('$user_password')";
//用用戶(hù)名和密碼進(jìn)行查詢(xún)
$data = mysqli_query($dbc,$query);
//若查到的記錄正好為一條,則設(shè)置COOKIE,同時(shí)進(jìn)行頁(yè)面重定向
if(mysqli_num_rows($data)==1){
$row = mysqli_fetch_array($data);
setcookie('user_id',$row['user_id']);
setcookie('username',$row['username']);
$home_url = 'loged.php';
header('Location: '.$home_url);
}else{//若查到的記錄不對(duì),則設(shè)置錯(cuò)誤信息
$error_msg = 'Sorry, you must enter a valid username and password to log in.';
}
}else{
$error_msg = 'Sorry, you must enter a valid username and password to log in.';
}
}
}else{//如果用戶(hù)已經(jīng)登錄,則直接跳轉(zhuǎn)到已經(jīng)登錄頁(yè)面
$home_url = 'loged.php';
header('Location: '.$home_url);
}
?>
<html>
<head>
<title>Mismatch - Log In</title>
<link rel="stylesheet" type="text/css" href="style.css" />
</head>
<body>
<h3>Msimatch - Log In</h3>
<!--通過(guò)$_COOKIE['user_id']進(jìn)行判斷,如果用戶(hù)未登錄,則顯示登錄表單,讓用戶(hù)輸入用戶(hù)名和密碼-->
<?php
if(empty($_COOKIE['user_id'])){
echo '<p class="error">'.$error_msg.'</p>';
?>
<!-- $_SERVER['php_SELF']代表用戶(hù)提交表單時(shí),調(diào)用自身php文件 -->
<form method = "post" action="<?php echo $_SERVER['php_SELF'];?>">
<fieldset style="width:250px;">
<legend>Log In</legend>
<label for="username">Username:</label>
<!-- 如果用戶(hù)已輸過(guò)用戶(hù)名,則回顯用戶(hù)名 -->
<input type="text" id="username" name="username"
value="<?php if(!empty($user_username)) echo $user_username; ?>" />
<br/>
<label for="password">Password:</label>
<input type="password" id="password" name="password"/>
</fieldset>
<br/>
<input type="submit" value="Log In" name="submit"/>
</form>
<?php
}
?>
</body>
</html>
效果圖:
復(fù)制代碼 代碼如下:
<?php
//已登錄頁(yè)面,顯示登錄用戶(hù)名
if(isset($_COOKIE['username'])){
echo 'You are Logged as '.$_COOKIE['username'].'<br/>';
//點(diǎn)擊“Log Out”,則轉(zhuǎn)到logOut.php頁(yè)面進(jìn)行cookie的注銷(xiāo)
echo '<a href="logOut.php"> Log Out('.$_COOKIE['username'].')</a>';
}
/**在已登錄頁(yè)面中,可以利用用戶(hù)的cookie如$_COOKIE['username']、
* $_COOKIE['user_id']對(duì)數(shù)據(jù)庫(kù)進(jìn)行查詢(xún),可以做好多好多事情*/
?>
效果圖:
復(fù)制代碼 代碼如下:
<?php
/**cookies注銷(xiāo)頁(yè)面*/
if(isset($_COOKIE['user_id'])){
//將各個(gè)cookie的到期時(shí)間設(shè)為過(guò)去的某個(gè)時(shí)間,使它們由系統(tǒng)刪除,時(shí)間以秒為單位
setcookie('user_id','',time()-3600);
setcookie('username','',time()-3600);
}
//location首部使瀏覽器重定向到另一個(gè)頁(yè)面
$home_url = 'logIn.php';
header('Location:'.$home_url);
?>
php技術(shù):php中使用cookie來(lái)保存用戶(hù)登錄信息的實(shí)現(xiàn)代碼,轉(zhuǎn)載需保留來(lái)源!
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